JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

Let

a_1, a_2, a_3, \ldots

be terms of an A.P. If

\frac{a_1+a_2+\ldots+a_p}{a_1+a_2+\ldots+a_q}=\frac{p^2}{q^2}, p \neq q

, then

\frac{a_6}{a_{21}}

equals

View answer and explanation

Correct option: D

\frac{11}{41}

Option D (11/41) is correct because the ratio a6/a21 is calculated using the given condition and properties of A.P.

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