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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If Hn=1+12+13+…+1n  ,{H_n} = 1 + \frac{1}{2} + \frac{1}{3} + \ldots + \frac{1}{n}\;, then the value of Sn=1+32+53+…+2n−1n{S_n} = 1 + \frac{3}{2} + \frac{5}{3} + \ldots + \frac{{2n - 1}}{n} is
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Correct option: B
2n−Hn2n - {H_n}
Option B (2n−Hn2n - {H_n}) is correct because the series can be rewritten and simplified using the definition of HnH_n.

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