NEET UG PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1

A bar magnet of magnetic moment

M

and moment of inertia

I

is freely suspended such that the magnetic axial line is in the direction of magnetic meridian. If the magnet is displaced by a very small angle (

\mathrm{\theta }

), the angular acceleration is (Magnetic induction of earth’s horizontal field

= {B_H}

)

View answer and explanation

Correct option: A

\frac{{M{B_{H\;}}\mathrm{\theta }}}{I}

Option A (

\frac{{M{B_{H\;}}\mathrm{\theta }}}{I}

) is correct because it represents the angular acceleration derived from the torque equation for a magnetic dipole in a magnetic field.

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\vec A = 2\vec i - 3\vec j + 6\vec k\,{m^2}

\vec B = - 3\vec i + \vec j + 2\vec k\,\left( {Wb/{m^2}} \right)

250\;joule

10\;kg

50\;Hz

7.5\;gm/c{m^3}

M

B