JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

\lim \limits_{{x \rightarrow \infty}}\left(1+\frac{a}{x}+\frac{b}{x^2}\right)^{2 x}=e^2

, then

View answer and explanation

Correct option: C

a=1, b \in R

Option C (

a=1, b \in R

) is correct because by evaluating the limit, we find that

a=1

, while

b

can be any real number.

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