JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

1 Easy

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Application +4 | -1

If the circles

{x^2} + {y^2} + 2x + 2ky + 6 = 0

and

{x^2} + {y^2} + 2ky + K = 0

intersect orthogonally, then

k

View answer and explanation

Correct option: A

2\,\,\mathrm{or} - \frac{3}{2}

Option A (

2\,\,\mathrm{or} - \frac{3}{2}

) is correct because these are the values of k that satisfy the orthogonality condition for the two circles.

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