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JEE CHEMISTRY MCQ: AMINES

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Analyzing +4 | -1
An aromatic amine (A)\left( A \right) was treated with alcoholic potash and another compound (Y)\left( Y \right) when a foul smeling gas was formed with formula C6H5NC{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{NC}. (Y)\left( Y \right) was formed by reacting a compound (Z)\left( Z \right) with Cl2\mathrm{C}{\mathrm{l}_2} in the presence of slaked lime. Compound (Z)\left( Z \right) is:
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Correct option: C
CH3COCH3\mathrm{C}{\mathrm{H}_3}\mathrm{COC}{\mathrm{H}_3}
The correct answer is C (CH3COCH3\mathrm{C}{\mathrm{H}_3}\mathrm{COC}{\mathrm{H}_3}) because it leads to the formation of chloroform, which reacts with the amine to form phenyl isocyanide.

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