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JEE MATHEMATICS MCQ: LIMITS

1 Easy
1 of 1
Application +4 | -1
lim⁡x→π6  sin⁡2xsin⁡x\lim\limits_{x \to \frac{\pi }{6}} \,\,\frac{{\sin 2x}}{{\sin x}} is equal to
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Correct option: A
3\sqrt 3
Option A (3\sqrt 3) is correct because by simplifying the expression using trigonometric identities, the limit evaluates to the square root of 3.

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