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JEE MATHEMATICS MCQ: PARABOLA

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Analyzing +4 | -1
The locus of the vertices of the family of parabolas y=a3x23+a2x2−2ay=\frac{a^3 x^2}{3}+\frac{a^2 x}{2}-2 a is
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Correct option: A
xy=10564x y=\frac{105}{64}
Option A (xy=10564x y=\frac{105}{64}) is correct because finding the vertex of the parabola and eliminating the parameter 'a' leads to the given locus.

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