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JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy
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Application +4 | -1
If   x  cos⁡  θ=y  cos⁡(θ+2π3)=z  cos⁡(θ+4π3)  \;x\,\,\cos \,\,\mathrm{\theta } = y\,\,\cos \left( {\mathrm{\theta } + \frac{{2\pi }}{3}} \right) = \mathrm{z}\,\,\cos \left( {\mathrm{\theta } + \frac{{4\pi }}{3}} \right)\;, then the value of 1x+1y+1z\frac{1}{x} + \frac{1}{y} + \frac{1}{\mathrm{z}} is equal to
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Correct option: C
0
Option C (0) is correct because the sum of the cosines with the given phase shifts equals zero, leading to the result 1/x + 1/y + 1/z = 0.

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