JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

The sum of infinite terms of a decreasing GP is equal to the greatest value of the function

f(x)=x^3+3 x-9

in the interval

[-2,3]

and the difference between the first two terms is

f^{\prime}(0)

. Then, the common ratio of a GP is

View answer and explanation

Correct option: C

\frac{2}{3}

Option C (

\frac{2}{3}

) is correct because by setting up the equations based on the given conditions and solving for the common ratio, we find that r =

\frac{2}{3}

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}