JEE CHEMISTRY MCQ: REDOX REACTIONS

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Analyzing +4 | -1

Given below the two statements:
Statement I: The

{E^\mathrm{o}}

value for

C{e^{4 + }}/C{e^{3 + }}

is + 1.74 V.
Statement II:

Ce

is more stable in

C{e^{4 + }}

state than

C{e^{3 + }}

state.
In the light of the above statement, choose the correct answer from the options given below:

View answer and explanation

Correct option: D

Statement I is correct but statement II is incorrect

Option D is correct because Statement I is correct (E° value for Ce4+/Ce3+ is +1.74 V), but Statement II is incorrect (Ce3+ is more stable than Ce4+).

More Questions from REDOX REACTIONS

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The oxidation number of

\mathrm{H}

in sodium hydride is A reagent, which can decrease the oxidation number of an element, is called Consider the following decomposition reaction

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

In the above reaction, Assertion (A):

\mathrm{HNO}_3

acts as oxidizing agent.

Reason (R): Oxidation no. of nitrogen is +5, no increase in oxidation no. beyond +5 can occur. The oxidation no. of

\mathrm{HNO}_3

can only decrease. Assertion :- Bromide ion is serving as a reducing agent in the reaction.

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

Reason :- Oxidation number of

\mathrm{Br}

increases from

-1

+5.

A substance, that by its sharp colour change indicates the completion of reaction is known as :