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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
lim⁡x→π482−(cos⁡x+sin⁡x)72−2sin⁡2x\lim\limits_{x \to \frac{\pi }{4}} \frac{{8\sqrt 2 - {{\left( {\cos x + \sin x} \right)}^7}}}{{\sqrt 2 - \sqrt 2 \sin 2x}} is equal to
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Correct option: A
14
Option A (14) is correct because applying L'Hopital's rule twice simplifies the limit to a determinate form.

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