JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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L=\lim \limits_{{n \rightarrow \infty}} \frac{1 \cdot 2 \cdot 3+2 \cdot 3 \cdot 4+3 \cdot 4 \cdot 5+\ldots \text { upto } n \text { terms }}{n(1 \cdot 2+2 \cdot 3+3 \cdot 4+\ldots \text { upto } n \text { terms })}

is equal to

View answer and explanation

Correct option: A

\frac{3}{4}

Option A (

\frac{3}{4}

) is correct because after simplifying the numerator and denominator using summation formulas and taking the limit, the expression evaluates to

\frac{3}{4}

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\frac{3}{4}