JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

If the curves

2 x^2+3 y^2=6

and

a x^2+4 y^2=4

intersect orthogonally, then

a=

View answer and explanation

Correct option: A

Option A (2) is correct because the value of 'a' for the curves to intersect orthogonally is calculated to be 2.

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\mathrm{C}

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\theta = \left( {2k + 1} \right)\pi ,\;k \in Z