General value of ${\rm{\theta }}$ satisfying the equation ${\tan ^2}\,\,{\rm{\theta }} + \sec \,\,2{\rm{\theta }} = 1$ is

$m\pi ,\;\,n\pi + \frac{\pi }{3}$

$m\pi ,\;\,n\pi \;\,\, \pm \,\,\frac{\pi }{6}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

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Analyzing +4 | -1

General value of

\mathrm{\theta }

satisfying the equation

{\tan ^2}\,\,\mathrm{\theta } + \sec \,\,2\mathrm{\theta } = 1

View answer and explanation

Correct option: B

m\pi ,\;\,n\pi \;\,\, \pm \,\,\frac{\pi }{3}

Option B (

m\pi ,\;\,n\pi \;\,\,\pm \,\,\frac{\pi }{3}

) is correct because it represents the general solutions obtained by solving the given trigonometric equation.

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\sin \,\,x\,\,\;cos\,\,3x = \sin \,\,3x\,\,\cos \,\,5x

\left[ {0,\;\,\frac{\pi }{2}} \right]

\left( {x,\,y} \right)

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\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1

\mathrm{X}

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\tan x