If the sum of $n$ terms of the series $704 + \frac{1}{2}\left( {704} \right) + \frac{1}{4}\left( {704} \right) + \ldots {\rm{and}},1984 - \frac{1}{2}\left( {1984} \right) + \frac{1}{4}\left( {1984} \right) \ldots $ are equal, then $n = $

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

If the sum of

n

terms of the series

704 + \frac{1}{2}\left( {704} \right) + \frac{1}{4}\left( {704} \right) + \ldots \mathrm{and},1984 - \frac{1}{2}\left( {1984} \right) + \frac{1}{4}\left( {1984} \right) \ldots

are equal, then

n =

View answer and explanation

Correct option: A

Option A (5) is correct because the sum of the two series are equal when n=5, which is found by solving the equation formed by equating the sums.

Practice All Chapter MCQs →

A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}