JEE CHEMISTRY MCQ: HYDROCARBONS

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Ca{C_2}\xrightarrow{{{H_2}O}}A\xrightarrow[{H{g^{2 + }}}]{{dil.{H_2}S{O_4}}}B\xrightarrow[{{H_2}}]{{Ni}}C

end product is

View answer and explanation

Correct option: C

{C_2}{H_5}OH

Option C (

{C_2}{H_5}OH

) is correct because the sequence of reactions involves hydration of calcium carbide to acetylene, followed by hydration of acetylene to acetaldehyde, and finally, reduction of acetaldehyde to ethanol.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: