Two identical containers $X$ and $Y$ with friction less pistons contain the same ideal gas at the same temperature and the same volume $V$. The mass of gas $X$ is $m_x$ and that of $Y$ is $m_y$. The gas in each cylinder is now allowed to expand isothermally to the same final volume $2 V$. The change in the pressure in $X$ and $Y$ are found to be $\Delta P$ and $3 \Delta P$ respectively. Then,

JEE PHYSICS MCQ: THERMODYNAMICS

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Analyzing +4 | -1

Two identical containers

X

and

Y

with friction less pistons contain the same ideal gas at the same temperature and the same volume

V

. The mass of gas

X

m_x

and that of

Y

m_y

. The gas in each cylinder is now allowed to expand isothermally to the same final volume

2 V

. The change in the pressure in

X

and

Y

are found to be

\Delta P

and

3 \Delta P

respectively. Then,

View answer and explanation

Correct option: C

3 m_x=m_y

Option C (

3 m_x=m_y

) is correct because the change in pressure is inversely proportional to the mass of the gas, leading to the relationship

3m_x = m_y