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JEE CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES
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+4 | -1
Maximum number of orbitals in excited state of . Electronegativity (Pauling scale) of most electronegative element . Then find value of .
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Correct option: A
4
Option A (4) is correct because the maximum number of orbitals in the 3rd excited state is 16, and the electronegativity of Fluorine is 4.0, so 16/4 = 4.
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