Back to CHEMICAL BONDING & MOLECULAR STRUCTURE

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Medium

1 of 1

Analyzing +4 | -1

Arrange the following in order of increasing dipole moment (I) Toluene (II)

m

- dichlorobenzene (III)

o

- dichlorobenzene (IV)

p

- dichlorobenzene :

View answer and explanation

Correct option: B

IV < I < II < III

The correct answer is B (IV < I < II < III) because dipole moment increases as follows: para < toluene < meta < ortho due to vector addition of bond dipoles.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

Practice All Chapter MCQs →

The hybridization in sulphur dioxide is

\mathrm{C}{\mathrm{O}_2}

has the same geometry as:

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

The pair of molecules forming strongest hydrogen bonds are Paramagnetism is shown by Which statement is correct? Assertion (A) :

{BF}_3

is a weaker Lewis acid than

{BCl}_3

.

Reason (R) : The planar

{BF}_3

molecule is stabilised to a greater extent than

{BCl}_3

{B}-X \pi

-bonding.