The angle between the lines in ${x^2} - xy - 6{y^2} - 7x + 31y - 18 = 0$ is

JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

1 Easy

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Application +4 | -1

The angle between the lines in

{x^2} - xy - 6{y^2} - 7x + 31y - 18 = 0

View answer and explanation

Correct option: B

45^\circ

Option B (

45^\circ

) is correct because the angle between the lines is calculated using the formula involving the coefficients of the quadratic equation.

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