Question

A uniformly charged disc of radius $R$ having surface charge density $\sigma $ is placed in the xy- plane with its centre at the origin. Find the electric field intensity along the $z$ –axis at a distance $Z$ from origin

Accepted Answer

$E = \frac{\sigma }{{2{\varepsilon _0}}}\left( {1 - \frac{{\rm{Z}}}{{\sqrt {({Z^2} + {R^2})} }}} \right)$

Answer

$E = \frac{\sigma }{{2{\varepsilon _0}}}\left( {1 + \frac{{\rm{Z}}}{{\sqrt {({Z^2} + {R^2})} }}} \right)$

Answer

$E = \frac{{2{\varepsilon _0}}}{\sigma }\left( {\frac{1}{{\sqrt {({Z^2} + {R^2})} }} + {\rm{Z}}} \right)$

Answer

$E = \frac{\sigma }{{2{\varepsilon _0}}}\left( {\frac{1}{{\sqrt {({Z^2} + {R^2})} }} + \frac{1}{{{{\rm{Z}}^2}}}} \right)$

NEET UG PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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