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NEET UG PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

1 Easy

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Application +4 | -1

An iron is placed parallel to the magnetic field of intensity

2000 \frac{\mathrm{A}}{\mathrm{m}}

. The magnetic flux through the rod is

6 \times 10^{-4} \mathrm{~Wb}

and its cross-sectional area is

3 \mathrm{~cm}^2

. The magnetic permeability of the rod in

\frac{\mathrm{W b}}{\mathrm{A-m}}

is

View answer and explanation

Correct option: B

10^{-3}

Option B (

10^{-3}

) is correct because the magnetic permeability is calculated using the magnetic flux, magnetic field intensity, and cross-sectional area.

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Assertion (A): Whenever the magnetic flux linked with a closed coil changes there will be an induced emf as well as an induced current.

Reason (R): According to Faraday, the induced emf is inversely proportional to the rate of change of magnetic flux linked with a coil. The coefficient of mutual inductance of two coils is

6\,\,mH

. If the current flowing in one is

2\,\,ampere

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(I)If magnetic field,

\mathrm{B = 0}

, then magnetic flux is also zero.
(II)If magnetic flux,

\phi = 0,

then magnetic field is also zero. The coefficient of self inductance of a solenoid is 0.18 mH. If a rod of soft iron of relative permeability 900 is inserted, then the coefficient of self inductance (in mH ) will become nearly: A uniformly wound solenoidal coil of self inductance

1.8 \times {10^{ - 4}}

H and resistance 6 Ω is broken up into two identical coils. These identical coils are then connected in parallel across a 12 V battery of negligible resistance. The time constant of the current in the circuit 