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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1
The electric field in a certain region is given by E⃗=5i^−3j^kV/m.\vec{E}=5 \hat{i}-3 \hat{j} k V / m. The potential difference VB−VAV_B-V_A between points AA and B,B, having coordinates (4,0,3) m(4,0,3) \,\mathrm{m} and (10,3,0) m(10,3,0) \,\mathrm{m} respectively, is equal to
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Correct option: B
−21 kV-21 \,\mathrm{kV}
Option B (−21 kV-21 \,\mathrm{kV}) is correct because the potential difference is calculated by integrating the electric field along the path between the two points.

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