NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

The equation of trajectory of projectile is

y = \sqrt 3 x - \frac{g}{2}{x^2}

the horizontal range for projectile is

View answer and explanation

Correct option: C

\frac{{2\sqrt 3 }}{g}

Option C (

\frac{{2\sqrt 3 }}{g}

) is correct. The horizontal range is calculated using the trajectory equation and finding the x-intercept.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

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\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)