JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Medium

1 of 1

Application +4 | -1

An electron revolves round

\mathrm{Li}^{2+}

nucleus at a distance of

1.587\,\mathop {\text{A}}\limits^ \circ

. The speed of electron should be

View answer and explanation

Correct option: A

2.188 \times 10^6 \mathrm{~m} / \mathrm{s}

Option A (

2.188 \times 10^6 m/s

) is correct because it calculates the speed of the electron using the Bohr model and the given radius for Li²⁺.

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →

n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.