JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

A continuous and differentiable function

f(x)

satisfy the functional equation

f(x+y)=\frac{f(x) f(y)}{f(x)+f(y)}

f(1)=32

then

f(4)=

View answer and explanation

Correct option: A

Option A (8) is correct because by substituting the functional equation into a simpler form and using the given condition

f(1)=32

, we can find the value of

f(4)

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