JEE CHEMISTRY MCQ: Equilibrium

1 Medium

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Application +4 | -1

For the following gaseous equilibria

\mathrm{X}, \mathrm{Y}

and

\mathrm{Z}

300 \mathrm{~K}

\mathrm{X}: 2{SO}_2+{O}_2 \rightleftharpoons {SO}_3

\begin{aligned} & \text {Y}: {PCl}_5 \rightleftharpoons {PCl}_3+{Cl}_2 \\ & \mathrm{Z}: 2 {HI} \rightleftharpoons {H}_2+{I}_2 \end{aligned}

ratio of

K_p

and

K_C

in the increasing order is

View answer and explanation

Correct option: C

\mathrm{X} < \mathrm{Z} < \mathrm{Y}

Option C (

\mathrm{X} < \mathrm{Z} < \mathrm{Y}

) is correct because it correctly orders the ratio of

K_p

K_C

based on the change in the number of moles of gas (

\Delta n_g

) for each reaction.

More Questions from Equilibrium

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\mathrm{K}_1

\mathrm{K}_2

\mathrm{N}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})\quad\ldots

\mathrm{NO}(\mathrm{g}) \rightleftharpoons \frac{1}{2} \mathrm{~N}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})\quad\ldots

K{a_1},\,\,\,K{a_2}\,\,\,\mathrm{and}\,\,\,K{a_3}

\begin{array}{l} {H_2}S\leftrightharpoons{H^ + } + H{S^ - }\\ H{S^ - }\leftrightharpoons{H^ + } + {S^{2 - }}\\ {H_2}S\leftrightharpoons2{H^ + } + {S^{2 - }} \end{array}

K{a_1},\,\,K{a_2}\,,K{a_3}

\mathrm{pH}

0.1 \mathrm{~M}-\mathrm{N}_2 \mathrm{H}_4

\mathrm{N}_2 \mathrm{H}_4,

K_{{b}_1}=3.6 \times 10^{-6}, K_{{b}_2}=6.4 \times 10^{-12}, \log 2=0.3

\log 3=0.48

{\text{Ba}}{{\text{O}}_2}(s) \rightleftharpoons {\text{BaO}}(s) + {{\text{O}}_2}(g);\Delta H = - {\text{ve}}.

\text{O}_2