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JEE MATHEMATICS MCQ: LIMITS

1 Easy
1 of 1
Analyzing +4 | -1
If f(1)=g(1)=2f\left( 1 \right) = g\left( 1 \right) = 2, then lim⁡x→1f(1)g(x)−f(x)g(1)−f(1)+g(1)f(x)−g(x)\lim\limits_{x \to 1} \frac{{f\left( 1 \right)g\left( x \right) - f\left( x \right)g\left( 1 \right) - f\left( 1 \right) + g\left( 1 \right)}}{{f\left( x \right) - g\left( x \right)}} is equal to
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Correct option: D
−2- 2
Option D (-2) is correct because simplifying the expression and applying the given conditions leads to the answer -2.

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