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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
If lim⁡x→0(1+a3)+8e1/x1+(1−b3)e1/x=2\lim \limits_{{x \rightarrow 0}} \frac{\left(1+a^3\right)+8 e^{1 / x}}{1+\left(1-b^3\right) e^{1 / x}}=2, then
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Correct option: A
a=1,b=(−3)1/3a=1, b=(-3)^{1 / 3}
Option A (a=1,b=(−3)1/3a=1, b=(-3)^{1 / 3}) is correct because by comparing coefficients after taking the limit as x approaches 0, we find that a=1a=1 and b=(−3)1/3b=(-3)^{1/3}.

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