The correct order of increasing $\left[ {{{\rm{H}}_3}{{\rm{O}}^ + }} \right]$ in the following aqueous solutions is:

$0.01\;M\;{\rm{NaN}}{{\rm{O}}_2} < 0.01\;M\;{\rm{NaCl}} < 0.01\;M\;{{\rm{H}}_2}{\rm{S}} < 0.01\;M\;{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$

$0.01\;M\;{{\rm{H}}_2}{\rm{S}} < 0.01\;M\;{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4} < 0.01\;M\;{\rm{NaCl}} < 0.01\;M\;{\rm{NaN}}{{\rm{O}}_2}$

$0.01\;M\;{\rm{NaCl}} < 0.01\;M\;{\rm{NaN}}{{\rm{O}}_2} < 0.01\;M\;{{\rm{H}}_2}{\rm{S}} < 0.01\;M\;{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$

$0.01\;M\;{{\rm{H}}_2}{\rm{S}} < 0.01\;M\;{\rm{NaN}}{{\rm{O}}_2} < 0.01\;M\;{\rm{NaCl}} < 0.01\;M\;{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$

JEE CHEMISTRY MCQ: Equilibrium

1 Medium

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Analyzing +4 | -1

The correct order of increasing

\left[ {{\mathrm{H}_3}{\mathrm{O}^ + }} \right]

in the following aqueous solutions is:

View answer and explanation

Correct option: C

0.01\;M\;\mathrm{NaN}{\mathrm{O}_2} < 0.01\;M\;\mathrm{NaCl} < 0.01\;M\;{\mathrm{H}_2}\mathrm{S} < 0.01\;M\;{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

Option C (

0.01\;M\;\mathrm{NaN}{\mathrm{O}_2} < 0.01\;M\;\mathrm{NaCl} < 0.01\;M\;{\mathrm{H}_2}\mathrm{S} < 0.01\;M\;{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

) is correct because it correctly orders the solutions from lowest to highest hydronium ion concentration based on their acidic/basic properties.