Two forces $\overrightarrow {{{\rm{F}}_1}} \;\,and\,\overrightarrow {{{\rm{F}}_2}} $ are acting at right angles to each other. Then their resultant is

NEET UG PHYSICS MCQ: MOTION IN PLANE

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Two forces

\overrightarrow {{\mathrm{F}_1}} \;\,and\,\overrightarrow {{\mathrm{F}_2}}

are acting at right angles to each other. Then their resultant is

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Correct option: B

\sqrt {F_1^2 + F_2^2}

Option B (

\sqrt {F_1^2 + F_2^2}

) is correct because it represents the magnitude of the resultant vector when two forces are perpendicular, derived from the Pythagorean theorem.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)