JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The common difference of the A.P.

b_1, b_2 \ldots, b_m

is 2 more than the common difference of the A.P.

a_1, a_2, \ldots, a_n

. If

a_{40}=-159, a_{100}=-399

and

b_{100}=a_{70}

, then

b_1

is equal to

View answer and explanation

Correct option: D

-81

Option D (-81) is correct because it calculates the first term b_1 of the second A.P. using the given information about both A.P.s.

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