JEE CHEMISTRY MCQ: HYDROCARBONS

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Analyzing +4 | -1

A hydrocarbon containing 2 carbon atoms give Sabatier and Senderen’s reaction but does not give precipitate with ammoniacal silver nitrate solution. The hydrocarbon in question is:

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Correct option: C

Ethylene

Option D is correct because PF5 exhibits sp3d hybridization, not sp3d2 hybridization.

More Questions from HYDROCARBONS

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: