The points of extremum of the function $\phi \left( x \right) = \mathop \smallint \limits_1^x {e^{ - {t^2}/2}}\left( {1 - {t^2}} \right)dt$, are

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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The points of extremum of the function

\phi \left( x \right) = \int \limits_1^x {e^{ - {t^2}/2}}\left( {1 - {t^2}} \right)dt

, are

View answer and explanation

Correct option: B

x = 1,\; - 1

Option B (

x = 1, -1

) is correct because these are the points where the derivative of the function equals zero, indicating potential extrema.

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