Question

A compound $X\left( {{{\rm{C}}_5}{{\rm{H}}_8}} \right)$ reacts with ammoniacal ${\rm{AgN}}{{\rm{O}}_3}$ to give a white precipitate, and on oxidation with hot alkaline ${\rm{KMn}}{{\rm{O}}_4}$ gives the acid,${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CHCOOH}}$. Therefore, $X$ is

Accepted Answer

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CH}} - {\rm{C}} \equiv {\rm{CH}}$

Answer

${\rm{C}}{{\rm{H}}_2} = {\rm{CHCH}} = {\rm{CHC}}{{\rm{H}}_3}$

Answer

${\rm{C}}{{\rm{H}}_3}{\left( {{\rm{C}}{{\rm{H}}_2}} \right)_2}{\rm{C}} \equiv {\rm{CH}}$

Answer

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{C}} = {\rm{C}} = {\rm{C}}{{\rm{H}}_2}$

JEE CHEMISTRY MCQ: HYDROCARBONS

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