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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let ff be a continuous function that p(x)=∫−2af(t)∣x−t∣dtp(x)=\int\limits_{{-2}}^a f(t)|x-t| d t where x∈(−2,2)x \in(-2,2), then the value of ∫02p′′(x)f(x)dx\int\limits_{0}^2 \frac{p^{\prime \prime}(x)}{f(x)} d x is equal to
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Correct option: D
4
Option D (4) is correct because the integral simplifies to 4 after finding the second derivative of p(x) and substituting.

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