$A\xrightarrow{{{\rm{HCl}}}}{\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{C}} = {\rm{CHCOC}}{{\rm{H}}_3},A$ is

NEET UG CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

1 Easy

1 of 1

Analyzing +4 | -1

A\xrightarrow{{\mathrm{HCl}}}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{C} = \mathrm{CHCOC}{\mathrm{H}_3},A

View answer and explanation

Correct option: A

Acetone

Option A (Acetone) is correct because acetone reacts with HCl to form the given product through an addition reaction.