X- ray analysis shows that the unit cell length in ${\rm{NaCl}}$ is 562.8 pm. Calculate the density you would expect on this basis, ${N_A} = 6.023{\rm{x}}{10^{23}}{\rm{mo}}{{\rm{l}}^{ - 1}}$

NEET UG CHEMISTRY MCQ: SOLID STATE

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Application +4 | -1

X- ray analysis shows that the unit cell length in

\mathrm{NaCl}

is 562.8 pm. Calculate the density you would expect on this basis,

{N_A} = 6.023\mathrm{x}{10^{23}}\mathrm{mo}{\mathrm{l}^{ - 1}}

View answer and explanation

Correct option: B

2.179\,g\,c{m^{ - 3}}

Option B (

2.179\,g\,c{m^{ - 3}}

) is correct because it's the calculated density based on the given unit cell length.