JEE MATHEMATICS MCQ: FUNCTIONS

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Which one of the following functions is not invertible?

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Correct option: B

f: \mathbb{R} \rightarrow[0, \infty), f(x)=x^2

Option B (

f: \mathbb{{R}} \rightarrow[0, \infty), f(x)=x^2

) is correct because this function is not one-to-one over the entire real numbers since

f(x) = f(-x)

, and therefore not invertible.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}