JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

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Analyzing +4 | -1

The function

f(x)=\tan ^{-1}(\sin x+\cos x)

is an increasing function in

View answer and explanation

Correct option: D

\left(-\frac{\pi}{2}, \frac{\pi}{4}\right)

Option D (

(-\frac{{\pi}}{{2}}, \frac{{\pi}}{{4}})

) is correct because the function

f(x)=\tan^{-1}(\sin x + \cos x)

is increasing when its derivative is positive, which occurs on the interval

(-\frac{{\pi}}{{2}}, \frac{{\pi}}{{4}})

More Questions from INCREASING & DECREASING

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f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)