If radius of second orbit of $\mathrm{He}^{+}$is $\mathrm{x} \mathrm{nm}$ then the radius of the first orbit of $\mathrm{Li}^{2+}$ will be

JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Easy

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Application +4 | -1

If radius of second orbit of

\mathrm{He}^{+}

\mathrm{x} \mathrm{nm}

then the radius of the first orbit of

\mathrm{Li}^{2+}

will be

View answer and explanation

Correct option: C

\frac{x}{6} \mathrm{~nm}

Option C (

\frac{x}{6} \mathrm{~nm}

) is correct because the radius of an orbit is proportional to n²/Z, and the ratio of the radii can be calculated using the given information.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.