JEE MATHEMATICS MCQ: COMBINATIONS

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A gentlemen hosts a party of

(m+n)

guests and places '

m

' at one round table and the remaining '

n

' at the other round table. Number of ways the guests can be arranged is

View answer and explanation

Correct option: A

\frac{(m+n) !}{m \cdot n}

Option A (

\frac{{(m+n) !}}{{m \cdot n}}

) is correct because it represents the number of ways to arrange (m+n) guests into two groups of m and n and then arrange them around two round tables.

More Questions from COMBINATIONS

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A rectangle of dimension

m \times n

(

m

and

n

being odd) is divided into square of unit length by drawing horizontal and vertical lines. The number of rectangles having side of odd unit length is The number of ways selecting three numbers from 1 to 30, so as to exclude every selection of three consecutive number is: Team A consists of 7 boys and n girls and Team B has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams, when a boy plays against a boy and a girl plays against a girl, then n is equal to The number of ways choosing a committee of 4 woman and 5 men from 10 women and 9 men, if Mr.

A

refuses to serve on the committee when Ms.

B

is a member of the committee, is A man has 7 friends. In how many ways he can invite one or more of them for a tea party? If

{\;^{n + 2}}{C_8}:{\;^{n - 2}}{P_4} = \frac{{57}}{{16}}

, then

n

is equal to