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JEE PHYSICS MCQ: WAVE OPTICS

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A light wave is incident normally over a slit of width 24×10−5  cm24 \times {10^{ - 5}}\;cm. The angular position of second dark fringe from the central maxima is 30∘30^\circ. What is the wavelength of light
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Correct option: A
6000A∘6000\mathop \mathrm{A}\limits^ \circ
Option A (6000A∘6000\mathop \mathrm{A}\limits^ \circ) is correct because it is the wavelength calculated using the formula for the angular position of the second dark fringe in single-slit diffraction.

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