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NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

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The energy of electromagnetic wave in vacuum is given by the relation
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Correct option: D
12ε0E2+B22μ0\frac{1}{2} \varepsilon_0 \mathrm{E}^2+\frac{\mathrm{B}^2}{2 \mu_0}
Option D, 12ε0E2+B22μ0\frac{1}{2} \varepsilon_0 \mathrm{E}^2+\frac{\mathrm{B}^2}{2 \mu_0}, is correct because it represents the total energy density of an electromagnetic wave in vacuum, which is the sum of the electric and magnetic energy densities.

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