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NEET UG PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1
A force of 2.25 N acts on a charge of 15×10−415 \times {10^{ - 4}}. Calculate the intensity of electric field at that point
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Correct option: A
1500 NC−1\mathrm{N}{\mathrm{C}^{ - 1}}
Option A (1500 NC−1\mathrm{N}{\mathrm{C}^{ - 1}}) is correct because it is calculated by dividing the force by the charge.

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