JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Application +4 | -1

The line

x+y=2

is tangent to the curve

x^2=3-2 y

at its point

View answer and explanation

Correct option: A

(1,1)

Option A (

(1,1)

) is correct because by finding the derivative of the curve and setting it equal to the slope of the line, we can solve for the point of tangency.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z