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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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12−12.22+13.23−14.24+…\frac{1}{2} - \frac{1}{{{{2.2}^2}}} + \frac{1}{{{{3.2}^3}}} - \frac{1}{{{{4.2}^4}}} + \ldots is equal to
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Correct option: C
log⁡e(32){\log _e}\left( {\frac{3}{2}} \right)
Option C (log⁡e(32){\log _e}(\frac{3}{2})) is correct because the given series is a direct application of the Maclaurin series expansion of log⁡e(1+x)\log_e(1+x) with x=12x = \frac{1}{2}.

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