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JEE MATHEMATICS MCQ: LIMITS

1 Hard
1 of 1
Analyzing +4 | -1
For each x∈Rx \in R, let [x][x] be the greatest integer less than or equal to xx. Then, lim⁡x→0−x([x]+∣x∣)sin⁡[x]∣x∣\lim\limits_{x \to {0^ - }} \frac{{x([x] + \left| x \right|)\sin [x]}}{{\left| x \right|}} is equal to
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Correct option: C
- sin 1
Option C (- sin 1) is correct because it is the limit of the given expression as x approaches 0 from the left, obtained by substituting the greatest integer function and absolute value.

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