JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim\limits_{x \to \infty } {\left( {\frac{{3{x^2} + 2x + 1}}{{{x^2} + x + 2}}} \right)^{\frac{{6x + 1}}{{3x + 2}}}}

is equal to

View answer and explanation

Correct option: C

Option C (9) is correct because the limit can be evaluated by finding the limits of the base and exponent separately and then combining them.

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